Date to Day

Ported from my C++ code. Outputs the day given the date as input. Probably horrible python, this is my first ever python script :)

#!/usr/bin/python
def is_leap_year(year) :
	if(year%100 == 0 and year%400 != 0) :
		return 0

	if(year%4 != 0) :
		return 0

	return 1


def step_1(year) :
	century = year//100+1

	if(century%4 == 0) :
		return 0
	if(century%4 == 1) :
		return 6
	if(century%4 == 2) :
		return 4
	if(century%4 == 3) :
		return 2


def step_2(year, month) :
	if(not is_leap_year(year)) :
		last_leap_year = year
		while(not is_leap_year(last_leap_year)) :
			last_leap_year = last_leap_year-1

		return (((last_leap_year%100)//4)*5+(year-last_leap_year)+1)

	else :
		temp = (((year%100)//4)*5)
		if(month > 2) :
			return temp+1

		return temp


def step_3(month, date) :
		if(month==1) : return date
		if(month==2) : return 3+date
		if(month==3) : return 3+date
		if(month==4) : return 6+date
		if(month==5) : return 1+date
		if(month==6) : return 4+date
		if(month==7) : return 6+date
		if(month==8) : return 2+date
		if(month==9) : return 5+date
		if(month==10): return date
		if(month==11): return 3+date
		if(month==12): return 5+date


date  = int(raw_input())
month = int(raw_input())
year  = int(raw_input())
day   = 0

day += step_1(year)
day += step_2(year, month)
day += step_3(month, date)

if(day%7 == 0) : print "Saturday"
if(day%7 == 1) : print "Sunday"
if(day%7 == 2) : print "Monday"
if(day%7 == 3) : print "Tuesday"
if(day%7 == 4) : print "Wednesday"
if(day%7 == 5) : print "Thursday"
if(day%7 == 6) : print "Friday"